Question

An elevator accelerates upward at 1.2 m/s
2
.
The acceleration of gravity is 9.8 m/s
2
.
What is the upward force exerted by the
floor of the elevator on a(n) 72 kg passenger?
Answer in units of N.

Answer 1

the upward acceleration of the elevator adds to the gravitational force

f = m a = 72 kg * (9.8 m/s^2 + 1.2 m/s^2)

Answer 2

So it would be 72*11=792?

Answer 3

yup