Asked by Anonymous

An elevator accelerates upward at 1.2 m/s
2
.
The acceleration of gravity is 9.8 m/s
2
.
What is the upward force exerted by the
floor of the elevator on a(n) 87 kg passenger?

Answers

Answered by oobleck
F = ma = 87(9.8 + 1.2) = ___ N

and we write m/s^2 -- forget the newlines.
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