Asked by Tris
The roots of f(x) = (x^3-x^2-6x)/(-3x^2-3x+18) are mostly nearly:
Answers
Answered by
Damon
x (x^2 - x - 6) / [ (-3)(x^2 + x - 6) ] = 0
x (x-3)(x+2) / [ -3 (x-2)(x+3) ] = 0
x = 0 works
x = 3 works
x = -2 works
x (x-3)(x+2) / [ -3 (x-2)(x+3) ] = 0
x = 0 works
x = 3 works
x = -2 works
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