Asked by Olamide
A rocket is fired at 60° to the horizontal with an initial speed of 200 m/s.calculate it time of flight and it range on a horizontal plane
Answers
Answered by
Damon
Vertical problem first:
initial vertical speed = Vi = 200 sin 60 = 173 m/s up
V = Vi - 9.81 t
h = Vi t - 4.9 t^2
h is zero at start and at finish
0 = Vi t - 4.9 t^2 = t (Vi - 4.9 t)
so
t = Vi/4.9 at finish
now horizontal problem
u = 200 cos 60 = 100 until it crashes so
distance = 100 t = 100 (Vi/4.9)
initial vertical speed = Vi = 200 sin 60 = 173 m/s up
V = Vi - 9.81 t
h = Vi t - 4.9 t^2
h is zero at start and at finish
0 = Vi t - 4.9 t^2 = t (Vi - 4.9 t)
so
t = Vi/4.9 at finish
now horizontal problem
u = 200 cos 60 = 100 until it crashes so
distance = 100 t = 100 (Vi/4.9)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.