Asked by ajani.huff

32” TV height: 16” width: _____
32^2 + 16^2=
=1024 + 256
=1280
c = 35




• _____ TV height: 34” width: 61”
a^2+b^2
34^2 + 61^2
=1156 + 3721
=4877
c = 69



• 60” TV height: 30” width: _____

a^2 + b^2
=60^2 + 30^2
=3600 + 900
=4500
= 67


• _____ TV height: 20” width: 35”

a^2 + b^2
20^2 + 35^2
=400 + 1225
=1625
=40


• 52” TV height: _____ width: 45”

a^2 + b^2
52^2 + 45^2
=2704 + 2025
=4729
= 68


Answered by Reiny
No, you are simply using the two given numbers in each question as if they always represented the length and width.
That happened to work in #2 and #4, but the others are wrong.

The size of TV's is measured in terms of its diagonal, so Pythagoras would say:
T^2 = L^2 + W^2
So in each case you have to sub into the matching variable

e.g. #1
given: T = 32, W = 16, so
32^2 = L^2 + 16^2
1024 = L^2 + 256
768 = T^2
T = √768 = appr 28
(You had 35, how can the width be more than the diagonal??)
Answered by ajani huff
how can i fix it
Answered by Reiny
How can you fix it??
Did you not read my reply and the example I gave you?
Answered by ajani huff
its kinda confusing Mrs Reiny
Answered by Damon
t^2 = diagonal^2 = length^2 + width^2
That is what Reiny is telling you
so
length^2 = diagonal^2 - width^2
and
width^2 = diagonal^2 - length^2
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