Asked by Jim
Spherical balloon loses air at pi cubic inch per minute
What is rate of change at 10 inches?
What is the rate of change at 5 inches?
What is rate of change at 10 inches?
What is the rate of change at 5 inches?
Answers
Answered by
Reiny
Assuming you want the rate of change of the radius, since we are given the rate of change for the volume ....
V = (4/3)π r^3
dV/dt = 4π r^2 dr/dt
-π = 4π (10^2) dr/dt , -π since it said "loses", so it is decreasing
-1 = 400 dr/dt
dr/dt = -1/400
when the radius is 10 inches, the radius is decreasing at 1/400 inches/minute
repeat for 5 inches
V = (4/3)π r^3
dV/dt = 4π r^2 dr/dt
-π = 4π (10^2) dr/dt , -π since it said "loses", so it is decreasing
-1 = 400 dr/dt
dr/dt = -1/400
when the radius is 10 inches, the radius is decreasing at 1/400 inches/minute
repeat for 5 inches
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.