Question
A wave sent out from a source is reflected back to the surs in 1.0×10^-3 if the velocity of the wave is 3.0×10^8ms^-1 the distance of the reflection from the source.
Answers
henry2,
T = 1.0*10^-3/2 = 0.5*10^-3 = 5*10^-4 s.
d = V * T = 3*10^8 * 5*10^-4 =
d = V * T = 3*10^8 * 5*10^-4 =
Lovely
Very good and helpful for me.👍♥️😘