Asked by Mercy
A wave sent out from a source is reflected back to the source in 1.9x10^-3 seconds .if the velocity of the wave is 3.0x10^8 m/s, the distance of the reflecting surface from the source is ?
Answers
Answered by
Henry
d=V*T = 3*10^8 * (1.9*10^-3/2) = 2.85*10^5 m.
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