Asked by Andrea
A golf ball is thrown straight up with an initial speed of 24.0m/s. It is caught at the same distance above the ground. How high does the golf ball rise? How long does the golf ball stay in the air?
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Answers
Answered by
bobpursley
you know the initial KEnergy. Set PEnergy at the top and solve for max height.
for time in air, height initial = height final
hf=hi+1/2 gt^2+vi*time
solve for time in air, t
t= sqrt(2*vi/g)
for time in air, height initial = height final
hf=hi+1/2 gt^2+vi*time
solve for time in air, t
t= sqrt(2*vi/g)
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