Asked by Ashley

Hi, I'm new to Java. I've been working on this question, wrote the code and checked the results with some examples and it seems to be doing fine. I would be glad if any of the teachers can check the code for me.
Also, please do let me know if there's a more efficient way for writing the code.
Many thanks!

Question :

Write a Java program that replies either Leap Year or Not a Leap Year, when a year is given as keyboard input.
(i) A Year is a Leap Year if the year can be divided by 4 but not by 100
(eg: 1976).
(ii) A year that can be divided by both 4 and 100 is Leap Year if it can also
be divided by 400.


My code :
package exams;

import java.util.*;

public class Exams {

public static void main(String[] args) {

Scanner input = new Scanner(System.in);

int p, q, r, s;

System.out.print("Enter Year");
p = input.nextInt();

if(p%4==0){

if(p%100==0){

if(p%400==0){

System.out.println("Leap Year");
}

}

else if(p%100!=0){
System.out.println("Not a Leap Year");

}

}

}

}




Answers

Answered by Anonymous
int year;

System.out.print("Enter Year");
year = input.nextInt();
boolean leap = false;
if(year % 4 == 0)
{
if( year % 100 == 0)
{
// year is divisible by 400, hence the year is a leap year
if ( year % 400 == 0)
leap = true;
else
leap = false;
}
else
leap = true;
}
else
leap = false;
if(leap)
System.out.println(year + " is a leap year.");
else
System.out.println(year + " is not a leap year.");
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