Asked by Jay
                Hi i have to complete a dimond where its 9 on top and 2 bottom if tried all numbers . What are the 2 numbers that add to 2 but when multiplied is 9 
            
            
        Answers
                    Answered by
            Reiny
            
    "What are the 2 numbers that add to 2 but when multiplied is 9 ?"
let them be x and y
x+y=2 ----> y = 2-x
xy = 9
x(2-x) = 9
2x - x^2 - 9 = 0
x^2 - 2x + 9 = 0
This quadratic equation has no real solution ...
x = (2 ± √(4-4(1)(9)) )/2
= (2 ± √-32)/2 = (2 ± 4√2)/2
= 1 ± 2√-2
= 1 ± 2i , <----- these are both complex numbers, but they work for your condition stated.
sum: 1+2√2 i + 1-2√2 i = 2
product: (1+2√2 i)(1-2√2 i) = 1 - 2√2 i + 2√2 i - 8i^2 , but i^2 = -1
= 1 + 8 = 9
I don't have the foggiest idea what "complete a dimond where its 9 on top and 2 bottom if tried all numbers " means.
Not familiar with that type of English.
    
let them be x and y
x+y=2 ----> y = 2-x
xy = 9
x(2-x) = 9
2x - x^2 - 9 = 0
x^2 - 2x + 9 = 0
This quadratic equation has no real solution ...
x = (2 ± √(4-4(1)(9)) )/2
= (2 ± √-32)/2 = (2 ± 4√2)/2
= 1 ± 2√-2
= 1 ± 2i , <----- these are both complex numbers, but they work for your condition stated.
sum: 1+2√2 i + 1-2√2 i = 2
product: (1+2√2 i)(1-2√2 i) = 1 - 2√2 i + 2√2 i - 8i^2 , but i^2 = -1
= 1 + 8 = 9
I don't have the foggiest idea what "complete a dimond where its 9 on top and 2 bottom if tried all numbers " means.
Not familiar with that type of English.
                    Answered by
            Reiny
            
    near the middle , should have been:
= <b>1 ± 2√2 i</b> , <----- these are both complex numbers ....
    
= <b>1 ± 2√2 i</b> , <----- these are both complex numbers ....
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