Question

A hyperbola has a vertical transverse axis of length 6 and asymptotes of y = (2x/5)+2 and y = (-2x/5)-4.

I am having trouble finding the focal length. I mean I think I've found it, but apparently it's incorrect.

c = sqrt(a^2+b^2) = sqrt(5^2+2^2) = sqrt(29)
--> By the way, the eccentricity e = c/a = (sqrt(29))/2 = 2.69, which is correct. So I suppose a = 2 and b = 5.
focal length = 2c = 2(sqrt(29)) = 10.77 (supposedly incorrect)
as I recall, the asymptotes are y = b/a x, not a/b x
Regardless, what about the focal length I obtained? Is it correct?

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