first of all I don't see why the asymptotes were not reduced to
3x ± y = 0
work it backwards.
Recall that for
x^2/a^2 - y^2/b^2 = 1 (the general hyperbola)
the asymptotes are bx ± ay = 0
so b=3 and a=1
for a the equation
x^2 - y^2/9 = 1 or
9x^2 - y^2 = 9
I have to write the equation of a hyperbola whose center is (0,0) and which has a vertical transverse axis.
The equations of the asymptotes are 6x+2y=0 and 6x-2y=0.
I don't even know where to begin. Could someone help? Thanks.
1 answer
1 answer