Asked by CodyJinks
Paintball guns were originally developed to mark trees for logging. A forester aims his gun directly at a knothole in a tree that is 4.0 m above the gun. The base of the tree is 20 m away. The speed of the paintball as it leaves the gun is 50 m/s. How far below the knothole does the paintball strike the tree?
I need some direction on this one because I do not understand how it wont hit the hole. And maybe a quick how-to with some formulas
I need some direction on this one because I do not understand how it wont hit the hole. And maybe a quick how-to with some formulas
Answers
Answered by
R_scott
he aims directly at the hole , but gravity causes the projectile to drop
the horizontal velocity (V) of the projectile is ... 50 m/s * [20 / √(20^2 + 4^2)]
the time of flight (T) is ... 20 m / V
the drop of the projectile is ... 1/2 g T^2
... g is gravitational acceleration ... 9.81 m/s^2
the horizontal velocity (V) of the projectile is ... 50 m/s * [20 / √(20^2 + 4^2)]
the time of flight (T) is ... 20 m / V
the drop of the projectile is ... 1/2 g T^2
... g is gravitational acceleration ... 9.81 m/s^2
Answered by
CodyJinks
Thanks you legend
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