Asked by Ryn
The function has a vertical asymptote of x=2 The function has a removable discontinuity of x=-2 The function has a horizontal asymptote of y= 0 No x intercept Y-intercept is (0,-0.5) End Behavior f(x) --> 0, x? -oo f(x) ? 0, x ? oo
What is the rational function? Please help!!
( ‘oo’ is infinity btw)
What is the rational function? Please help!!
( ‘oo’ is infinity btw)
Answers
Answered by
oobleck
come on, just follow the steps:
<u>vertical asymptote of x=2</u>
y = 1/(x-2)
<u>removable discontinuity of x=-2</u>
y = (x+2)/((x-2)(x+2))
<u>horizontal asymptote of y= 0</u>
no adjustment needed, since the degree below is greater than that above
<u>No x intercept</u>
still no adjustment needed, since everywhere except x = -2, y = 1/(x-2), which has no x-intercept.
<u>y-intercept is (0,-0.5)</u>
(x+2)/((x-2)(x+2)) = 2/-4 = -0.5 at x=0, so we are done.
<u>vertical asymptote of x=2</u>
y = 1/(x-2)
<u>removable discontinuity of x=-2</u>
y = (x+2)/((x-2)(x+2))
<u>horizontal asymptote of y= 0</u>
no adjustment needed, since the degree below is greater than that above
<u>No x intercept</u>
still no adjustment needed, since everywhere except x = -2, y = 1/(x-2), which has no x-intercept.
<u>y-intercept is (0,-0.5)</u>
(x+2)/((x-2)(x+2)) = 2/-4 = -0.5 at x=0, so we are done.
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