x to right
y into screen
z up
F = q ( V cross B)
q = -1.6 * 10^-19 C scalar
V = 4 * 10^6 m/s in x direction
B = 0.20 T in y direction
so if q were POSITIVE force would be in UP (z direction)
however q is NEGATIVE, so force is in -z direction, down
since V and B are at 90 degrees, just multiply, sin of 90 = 1
F = 1.6*10^-19 * 4*10^6 * 0.20 Newtons downward
An electron accelerates from rest to the right, in a horizontally directed electric field. The electron then leaves the electric field at a speed of 4.0 × 106, entering a magnetic field of magnitude 0.20 T (Tesla) directed into the screen. Calculate the magnitude and direction of the magnetic force on the electron.
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