Asked by Harmony
A store had 50 bottles of olive oil. Each week, 40% of the olive oil bottles were sold and 20 new bottles arrived in shipments. Which recursive function best represents the number of bottles in the store, given that f(0) = 50?
f(n) = f(n − 1) ⋅ 0.6 + 20, n > 0
f(n) = 50 − f(n − 1) ⋅ 0.6 + 20, n > 0
f(n) = 50 − f(n − 1) ⋅ 0.4 + 20, n > 0
f(n) = f(n − 1) ⋅ 0.4 + 20, n > 0
f(n) = f(n − 1) ⋅ 0.6 + 20, n > 0
f(n) = 50 − f(n − 1) ⋅ 0.6 + 20, n > 0
f(n) = 50 − f(n − 1) ⋅ 0.4 + 20, n > 0
f(n) = f(n − 1) ⋅ 0.4 + 20, n > 0
Answers
Answered by
Damon
f(1) = .6(50) + 20 = 30 + 20 = 50
f(2) = .6(50) + 20 = 50
f(3) = .6(50) + 20 = 50 forever and ever, good inventory planning
well try them, but you do not have to try many :)
f(2) = .6(50) + 20 = 50
f(3) = .6(50) + 20 = 50 forever and ever, good inventory planning
well try them, but you do not have to try many :)
Answered by
Reiny
Calculate the first few terms using your description.
(If 40% are sold, then 60% remain)
f(0) = 50
f(1) = .6(50) + 20 , looks like f(1) = .6(f(0)) + 20 = 50
Well, isn't that special, the number of bottles remains at 50
#1 and #3 yield the same result
(If 40% are sold, then 60% remain)
f(0) = 50
f(1) = .6(50) + 20 , looks like f(1) = .6(f(0)) + 20 = 50
Well, isn't that special, the number of bottles remains at 50
#1 and #3 yield the same result
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.