Asked by ana
A tennis ball is dropped from 1.76 m above the
ground. It rebounds to a height of 0.928 m.
With what velocity does it hit the ground?
The acceleration of gravity is 9.8 m/s
2
ground. It rebounds to a height of 0.928 m.
With what velocity does it hit the ground?
The acceleration of gravity is 9.8 m/s
2
Answers
Answered by
Damon
I answered a virtually identical question recently, just a different drop height.
v = sqrt (2 g h)
to make it simple but for the two ways to get there see:
https://www.jiskha.com/questions/1802335/A-tennis-ball-is-dropped-from-1-93-m-above-the-ground-It-rebounds-to-a-height-of
v = sqrt (2 g h)
to make it simple but for the two ways to get there see:
https://www.jiskha.com/questions/1802335/A-tennis-ball-is-dropped-from-1-93-m-above-the-ground-It-rebounds-to-a-height-of
Answered by
Damon
By the way, the answer does not depend on the rebound. You hit at a certain speed v = sqrt (2 g h) ignoring air friction. Your rebound height depends on your elasticity (coef of restitution) and the ground consistency (not squishy)
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