Asked by Peter
A 10.0 cm long cylindrical glass tube, sealed at one end, is filled with ethanol. The mass of ethanol needed to fill the tube is found to be 11.82 g . The density of ethanol is 0.789 g/mL. Calculate the inner diameter of the tube in centimeters.
Answers
Answered by
DrBob222
What's the volume of the ethanol?
mass = volume in mL x density in g/mL
11.82 g = volume in mL x 0.789 g/mL
volume = 11.82/0.789 = about 15 but you need to redo all of these calculations.
Since the ethanol filled the container that is the volume of the container.
Vcontainer = pi*r^2*h.
You know volume, you know pi, you know h, substitute and solve for r. Then diameter is 2*radius.
Post your work if you get stuck.
mass = volume in mL x density in g/mL
11.82 g = volume in mL x 0.789 g/mL
volume = 11.82/0.789 = about 15 but you need to redo all of these calculations.
Since the ethanol filled the container that is the volume of the container.
Vcontainer = pi*r^2*h.
You know volume, you know pi, you know h, substitute and solve for r. Then diameter is 2*radius.
Post your work if you get stuck.
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