Asked by anonymous
Phoebe and Holden are on opposite sides of a tall tree, 125 m apart. the angles of elevation from each top of the tree are 47 degrees and 36 degrees. what is the height of the tree?
My Answer:
The top angle will be = 180 - (47 + 36) = 97°
then we use the sine law:
(height of tree / sin 47) = (Base / sin 97)
height of tree = (125 x sin 47) / sin 97 = 92.1 m
is my answer correct
My Answer:
The top angle will be = 180 - (47 + 36) = 97°
then we use the sine law:
(height of tree / sin 47) = (Base / sin 97)
height of tree = (125 x sin 47) / sin 97 = 92.1 m
is my answer correct
Answers
Answered by
oobleck
let's see. we can also say that
h cot47° + h cot36° = 125
h = 54.14
So, what's wrong with your solution?
The law of sines only works when applied to the same triangle.
h cot47° + h cot36° = 125
h = 54.14
So, what's wrong with your solution?
The law of sines only works when applied to the same triangle.
Answered by
anonymous
so my answer should be:
tan 47 = h/x
tan 36 = h/(125-x)
x*tan47 = 125*tan36-x*tan36
x = 125*tan36/[tan47+tan36]
x = 50.485 m
h = 54.138 m
tan 47 = h/x
tan 36 = h/(125-x)
x*tan47 = 125*tan36-x*tan36
x = 125*tan36/[tan47+tan36]
x = 50.485 m
h = 54.138 m
Answered by
henry2,
d1 + d2 = 125 m.
Tan47 = h/d1; h = d1*Tan 47 = (125-d2)Tan 47.
Tan36 = h/d2; h = d2*Tan36.
h = (125-d2)*Tan 47 = d2*Tan 36.
(125-d2)*Tan 47 = d2*Tan 36,
d2 = 74.4 m,
d1 = 125-74.4 = 50.6 m.
h = d2*Tan 36 = 74.4*Tan 36 = 54.1 m.
Tan47 = h/d1; h = d1*Tan 47 = (125-d2)Tan 47.
Tan36 = h/d2; h = d2*Tan36.
h = (125-d2)*Tan 47 = d2*Tan 36.
(125-d2)*Tan 47 = d2*Tan 36,
d2 = 74.4 m,
d1 = 125-74.4 = 50.6 m.
h = d2*Tan 36 = 74.4*Tan 36 = 54.1 m.
Answered by
anonymous
thanks henry2,
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