Asked by Anonymous
A 2kg stone is ejected upwards at an angle of 35 degrees with an initial velocity of 8 m/s from a cannon with an unknown initial height and lands on top of a platform that is 3 meters tall. The horizontal distance from the cannon to the platform is 7 meters. What is the initial height of cannon from which the stone is launched?
Answers
Answered by
oobleck
the horizontal speed is 8 cos35° m/s, so how long does it take to cover the 7m?
The height h of the stone is
h(t) = h<sub><sub>0</sub></sub> + (8 sin35°)t - 4.9t^2
plug in your t and solve for h<sub><sub>0</sub></sub> when h(t) = 7
The height h of the stone is
h(t) = h<sub><sub>0</sub></sub> + (8 sin35°)t - 4.9t^2
plug in your t and solve for h<sub><sub>0</sub></sub> when h(t) = 7
Answered by
oobleck
I mean h(t) = 3, the final height.
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