the horizontal speed is 8 cos35° m/s, so how long does it take to cover the 7m?
The height h of the stone is
h(t) = h0 + (8 sin35°)t - 4.9t^2
plug in your t and solve for h0 when h(t) = 7
A 2kg stone is ejected upwards at an angle of 35 degrees with an initial velocity of 8 m/s from a cannon with an unknown initial height and lands on top of a platform that is 3 meters tall. The horizontal distance from the cannon to the platform is 7 meters. What is the initial height of cannon from which the stone is launched?
2 answers
I mean h(t) = 3, the final height.
1 answer