Asked by Hillary
14.0 grams of diamonds are placed in a graduated cylinder. What is the new water level measurement on the graduated cylinder
Answers
Answered by
Damon
How would I know? I do not know diameter of cylinder or how much water was in it.
anyway:
the diamond sinks
it displaces a volume of water = 14 g / density of diamond in grams/cm^3
that volume in cm^3 = area of surface * height change
anyway:
the diamond sinks
it displaces a volume of water = 14 g / density of diamond in grams/cm^3
that volume in cm^3 = area of surface * height change
Answered by
oobleck
no idea, but it will have risen by the volume of the diamonds, right?
density = mass/volume, so ...
density = mass/volume, so ...
Answered by
DrBob222
mass diamond = volume x density
14.0 = volume in cc x 3.51 g/cc
volume in cc = 14.0/3.51 = about 4 cc
So the new water level in the graduated cylinder will be increased by about 4 cc.
14.0 = volume in cc x 3.51 g/cc
volume in cc = 14.0/3.51 = about 4 cc
So the new water level in the graduated cylinder will be increased by about 4 cc.
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