Asked by mia from math
Consider the function f(x)=tanx with a domain of 0<x<π2, where x is in radians.
What is the range of f−1(x)?
- 0<x<∞
- −∞<x<∞
- 0<f−1(x)<∞
- −∞<f−1(x)<∞
- 0<x<π2
- 0<f−1(x)<π2
What is the range of f−1(x)?
- 0<x<∞
- −∞<x<∞
- 0<f−1(x)<∞
- −∞<f−1(x)<∞
- 0<x<π2
- 0<f−1(x)<π2
Answers
Answered by
oobleck
the range of f<sup><sup>-1</sup></sup>(x) is the domain of f(x)
I assume you mean π/2
consider the graph of tan<sup><sup>-1</sup></sup>x
I assume you mean π/2
consider the graph of tan<sup><sup>-1</sup></sup>x
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