Compute enthalpy for 2P(s) + 3Cl2(g) --> 2PCl3(l) at -639.4 kJ/mol to 2P(s) + 6Cl2(g) --> 2PCl5(s) at -887 kJ/mol to PCl5(l) + Cl2(g) --> PCl5(s) no given heat

Answer 1

I don't understand the question.
PCl5(l) + Cl2(g) --> PCl5(s) can't be correct.

Answer 2

We can leave this question intact. I will update the code to prevent email addresses as a name.

Answer 3

That's a good idea.