Asked by June
If the theoretical enthalpy of a reaction is -602 KJ/mol and the actual enthalpy determined is -582, what is the percent error??
Answers
Answered by
DrBob222
I've seen this done two ways.
|602 - 582| = 20 as the absolute value.
Then (20/582)*100 = % error = 3.4%
Then I've seen %error =100* (exp value - accepted value)/accepted value and carry the sign forward. Personally I like the first one but critics say this doesn't tell if the error is above or below the accepted value.
|602 - 582| = 20 as the absolute value.
Then (20/582)*100 = % error = 3.4%
Then I've seen %error =100* (exp value - accepted value)/accepted value and carry the sign forward. Personally I like the first one but critics say this doesn't tell if the error is above or below the accepted value.
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