Asked by Golden
If a spring had a stiffness of 950 Newton meter, what work will be done in extending the spring by 60milimeters square
Answers
Answered by
Damon
Good grief, read what you type!
Newtons PER meter
I assume you mean 60 millimeters, not square
In other words maybe:
k = 950 N/m
x = 0.060 meters = 6* 10^-2 m
if so then
W = (1/2) k x^2
= 475(36*10^-4) Joules
= 1.71 J
or perhaps you mean x^2 = 60 *10^-6 m^2 ?
Newtons PER meter
I assume you mean 60 millimeters, not square
In other words maybe:
k = 950 N/m
x = 0.060 meters = 6* 10^-2 m
if so then
W = (1/2) k x^2
= 475(36*10^-4) Joules
= 1.71 J
or perhaps you mean x^2 = 60 *10^-6 m^2 ?
Answered by
Soni3D
Thanks a lot