Asked by Carl
how to find difference quotient for:
f(x) = 1/x+3
f(x) = 1/x+3
Answers
Answered by
bobpursley
So I am reading that as f(x)=(1/x) + 3
difference= f(x+e)-f(x)=1/(x+e) + 3 - 1/x -3= (x-x-e)/((x+e)(x))
difference quotent=difference/e= (- 1)/(x^2 +xe ) =
difference= f(x+e)-f(x)=1/(x+e) + 3 - 1/x -3= (x-x-e)/((x+e)(x))
difference quotent=difference/e= (- 1)/(x^2 +xe ) =
Answered by
oobleck
or, see your previous post of 1:48 pm
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.