Asked by Carl
how to find difference quotient for:
f(x) = 1/x+3
f(x) = 1/x+3
Answers
Answered by
bobpursley
So I am reading that as f(x)=(1/x) + 3
difference= f(x+e)-f(x)=1/(x+e) + 3 - 1/x -3= (x-x-e)/((x+e)(x))
difference quotent=difference/e= (- 1)/(x^2 +xe ) =
difference= f(x+e)-f(x)=1/(x+e) + 3 - 1/x -3= (x-x-e)/((x+e)(x))
difference quotent=difference/e= (- 1)/(x^2 +xe ) =
Answered by
oobleck
or, see your previous post of 1:48 pm