Asked by T
1. Find f^-1 for the function f(x)=3srtx-2 +8
2. Find the domain and range of f^-1 where f(x) = 1/3x+2
2. Find the domain and range of f^-1 where f(x) = 1/3x+2
Answers
Answered by
oobleck
1. swap variables and solve for the new y = f^-1(x)
x = 3√(y-2)+8
x-8 = 3√(y-2)
finish it up. Check your answer using the fact that if g(x) = f^-1(x) then
f(g(x)) = g(f(x)) = x
#2 well, f^-1(x) = (1/x - 2)/3
so, what do you think? Start by picturing (or, heck, actually graphing!)
y = 1/x
and then shift it and scale it.
x = 3√(y-2)+8
x-8 = 3√(y-2)
finish it up. Check your answer using the fact that if g(x) = f^-1(x) then
f(g(x)) = g(f(x)) = x
#2 well, f^-1(x) = (1/x - 2)/3
so, what do you think? Start by picturing (or, heck, actually graphing!)
y = 1/x
and then shift it and scale it.
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