Asked by Johnpaul11
Pls help me out on this question, Find the sum of this first 8 terms of the Arithmetic Progression. log x, log x2, logx3
Answers
Answered by
oobleck
recall that log x^n = n logx
So, your sequence is
logx, 2logx, 3logx, ...
= logx (1,2,3,...)
just an ordinary AP, so the sum is
logx * 8/2 (2 + 7*1) = 36 logx = log x^36
So, your sequence is
logx, 2logx, 3logx, ...
= logx (1,2,3,...)
just an ordinary AP, so the sum is
logx * 8/2 (2 + 7*1) = 36 logx = log x^36
Answered by
fatusin lawrence
The sum of the first 21 terms of the progression,-18,-15,-12,......is:
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