Evaluate

Question

Log4^5-log5^4/log 4^1/5+log 5^1/4

Answer 1

Recall that loga^b = b * loga
So, you have
log4^5-log5^4/log 4^1/5+log 5^1/4
(5log4 - 4log5)/(1/5 log4 + 1/4 log5)
once you start dividing logs, the usual rules get a bit trickier.
If all you want is a numeric value, then just plug and chug from here.

Answer 2

I still don't understand

Answer 3

Answer