Asked by Anonymous
                If radius of a circle is decreasing at the  rate of 3cm/s find rate of change of circumference when r=2
            
            
        Answers
                    Answered by
            oobleck
            
    C = 2πr
dC/dt = 2π dr/dt
Now just plug and chug. You will note that dC/dt does not depend on r.
    
dC/dt = 2π dr/dt
Now just plug and chug. You will note that dC/dt does not depend on r.
                    Answered by
            David
            
    OOBleck is correct, but just to be clear (and this answer is about a year late).
So plugging and chugging... 2 Pi times -3 cm/sec (negative since it's decreasing) Gives -6 Pi ... this is the "rate of change" of C. it is -6 Pi at r=2, and -6 Pi at any other r. so, it is independent of r. However, that does not tell us what the circumference actually is at any r. But without the derivative, we know C = 2 Pi r. at r=2, C = 4 Pi cm.
    
So plugging and chugging... 2 Pi times -3 cm/sec (negative since it's decreasing) Gives -6 Pi ... this is the "rate of change" of C. it is -6 Pi at r=2, and -6 Pi at any other r. so, it is independent of r. However, that does not tell us what the circumference actually is at any r. But without the derivative, we know C = 2 Pi r. at r=2, C = 4 Pi cm.
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