Asked by Elizabeth
We mix 119 grams of oxygen gas with 176 grams of argon in a volume of 520 mL at 116 Celsius. What will be the final pressure of the gas mixture? Answer in units of atm.
Answers
Answered by
oobleck
how many moles of gas do you have?
1 mole occupies 22.4L at STP
PV/T remains constant
so find P that works
1 mole occupies 22.4L at STP
PV/T remains constant
so find P that works
Answered by
DrBob222
mols O2 = 119/32 = ?
mols Ar = 176/39.95 = ?
Then PV = nRT
You solve for P.
V = 0.520 L
total n from above
R = 0.08206 L*atm/mol*K
T = 116 C converted to kelvin. K = 273 + C = ?
Post your work if you get stuck.
mols Ar = 176/39.95 = ?
Then PV = nRT
You solve for P.
V = 0.520 L
total n from above
R = 0.08206 L*atm/mol*K
T = 116 C converted to kelvin. K = 273 + C = ?
Post your work if you get stuck.
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