To calculate the heat of solution, you need to use the formula:
Heat of solution = (heat released or absorbed) / (mass of solute)
In this case, the heat released during the dissolution is 13.0 KJ, and the mass of the solute (anhydrous copper(ii)tetraoxosulphate(iv)) is 32 g.
Therefore, the heat of solution can be calculated as follows:
Heat of solution = 13.0 KJ / 32 g
To calculate the heat of solution, you need to convert the given mass of solute from grams to moles. To do this, you need to find the molar mass of anhydrous copper(ii)tetraoxosulphate(iv).
Molar mass of copper(ii)tetraoxosulphate(iv) (CuSO4) = atomic mass of Cu + 4 x (atomic mass of S + 4 x atomic mass of O)
The atomic masses of Cu, S, and O are:
Atomic mass of Cu = 63.55 g/mol
Atomic mass of S = 32.07 g/mol
Atomic mass of O = 16.00 g/mol
Molar mass of CuSO4 = 63.55 g/mol + 4 x (32.07 g/mol + 4 x 16.00 g/mol)
Once you have the molar mass of CuSO4, you can calculate the moles of copper(ii)tetraoxosulphate(iv) using the formula:
moles = mass / molar mass
Now, substitute the mass (32 g) and molar mass of CuSO4 into the formula to calculate the moles.
Finally, substitute the moles of copper(ii)tetraoxosulphate(iv) into the formula for the heat of solution to get your answer:
Heat of solution = 13.0 KJ / moles of CuSO4