(x^2-4)/(x+2) = (x+2)(x-2)/(x+2) = x-2 when x is not -2.
At x = -2, f(x) is undefined.
So, if f(x) is defined to be -4 when x = -2 then the discontinuity is removed.
If h(x) is equal to ((x^2)-4)/(x+2) when x is not -2, and h(x) is continuous for all real numbers, then what is the value of h(-2)?
1. 0
2. -2
3. -4
4. 2
5. This is impossible. There is an infinite discontinuity at x=-2
2 answers
it is -4 just solve the limit and plug in -2