Asked by Harry
There are 34 men and 32 women at a party. Of these, 13 men and 19 woman are married. If 2 people are chosen at random, find the probability that both will be men.
Answer: 17/65
Thanks for any help
Answer: 17/65
Thanks for any help
Answers
Answered by
Reiny
Number of possible pairs chosen is 2 from 66
= C(66,2) = 2145
number of pairs consisting of men
= C(34,2) = 561
prob(that your pair is made up of 2 men)
= 561/2145 = 17/65
The information that 13 men and 19 women are married is irrelevant.
= C(66,2) = 2145
number of pairs consisting of men
= C(34,2) = 561
prob(that your pair is made up of 2 men)
= 561/2145 = 17/65
The information that 13 men and 19 women are married is irrelevant.
Answered by
Harry
That makes so much sense. Thank you
Answered by
oobleck
Or, consider this as a problem of drawing without replacement:
P(man,man) = 34/66 * 33/65 = 1122/4290 = 17/65
P(man,man) = 34/66 * 33/65 = 1122/4290 = 17/65
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