Asked by Anonymous
Three strings are attached to an object. If one of the strings is pulled north with a force of 10 N and one of the other strings is pulled west with 15 N, what force must be applied to the third string so that the object does not move?
Please help me with this question! I am ok with vector questions but I don't know what to do with this one. I tried a couple of times and I couldn't get the right answer.
Please help me with this question! I am ok with vector questions but I don't know what to do with this one. I tried a couple of times and I couldn't get the right answer.
Answers
Answered by
Damon
Pull south with 10 N
Pull east with 15 Newtons
If you are doing this on an x y axis system then
Fx = 15
Fy = -10
|F| = sqrt(225 + 100) = sqrt (325) = 18.03
tan theta = Fy/Fx = -10/15
Pull east with 15 Newtons
If you are doing this on an x y axis system then
Fx = 15
Fy = -10
|F| = sqrt(225 + 100) = sqrt (325) = 18.03
tan theta = Fy/Fx = -10/15
Answered by
henry2,
F1+F2 = -15+10i =18N.[-33.7o]=18N.[33.7o] N. of W. = 18N.[146.3o]CCW.
F3 must be equal in magnitude to F1+F2 but opposite in direction:
F3 = 18N.[33.7o] S. of E. = 18N.[146.3+180] = 18N.[326.3o] CCW.
The system is in Equilibrium; therefore, the object does not move,
F3 must be equal in magnitude to F1+F2 but opposite in direction:
F3 = 18N.[33.7o] S. of E. = 18N.[146.3+180] = 18N.[326.3o] CCW.
The system is in Equilibrium; therefore, the object does not move,
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