Asked by uchenna
y is party constant and partly varies
as square of x when x =1, y=11 and when x=2, y=5, find the value of y when x=4.
as square of x when x =1, y=11 and when x=2, y=5, find the value of y when x=4.
Answers
Answered by
Damon
y = a x^2 + b
11 = a + b
5 = 4 a + b
-----------------
6 = -3 a
a = -2
b = 13 etc
11 = a + b
5 = 4 a + b
-----------------
6 = -3 a
a = -2
b = 13 etc
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