In a physics lab, Kate and Rob use a hanging mass and pulley system to exert a 2.45 N rightward force on a 0.500kg cart to accelerate across a low-friction track. If the resistance (ignore air resistance) force to the motion of the cart is 0.72N, then what is the cart's acceleration?

Question

I found the acceleration to be 3.46m/s/s.

Find the coefficient of the rolling friction.
Need help with this, please and thanks.

Answer 1

2.45 - .72 = .5 a
a = 3.46 agree
mu * m * g = .72
mu * 0.5 * 9.81 = .72
so mu = 2 * .72 / 9.81 = 0.147