2 answers
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u^2 = v^2 - 2as,
u = sqrt(v^2-2as).
v2 = u2 + 2as
What is the equivalent equation solved for u, when u > 0?
A. u=/v^2+2as
B. u=(v^2-2as)
C. u=/v^2-as / 2
D. u=/v^2-2as
I think its
D. /v^2-2as
or A. /V^2+2as
u = sqrt(v^2-2as).
v^2 = u^2 + 2as
Subtracting 2as from both sides:
v^2 - 2as = u^2
Taking the square root of both sides:
√(v^2 - 2as) = u
However, since u is specified to be greater than 0, we use the positive square root:
u = √(v^2 - 2as)
So, the correct answer is not D (/v^2-2as) because it lacks the square root operation. The correct answer is A (/v^2+2as), as it correctly represents the equation solved for u.