Asked by mssailormouth
                An object with a kinetic energy of 50 J is stopped in a distance of 0.01 m. The average force that stops the object is??
            
            
        Answers
                    Answered by
            mssailormouth
            
    KE=work
work=fd
force=w/d
50/0.01=
answer: 5000N
    
work=fd
force=w/d
50/0.01=
answer: 5000N
                    Answered by
            Damon
            
    Correct
    
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