Question
An elliptical arch is constructed which is 6 feet wide at the base and 9 feet tall in the middle. Find the height of the arch exactly 1 foot in from the base of the arch. looking for direction with what ellipse equation is and how to approach this problem
Answers
Place the center of the ellipse at (0,0)
You know that the semi-major axis (height) is a=9
the semi-minor axis (half the width) is b=3
So that means that
x^2/9 + y^2/81 = 1
Now just find y when x = 2
You know that the semi-major axis (height) is a=9
the semi-minor axis (half the width) is b=3
So that means that
x^2/9 + y^2/81 = 1
Now just find y when x = 2
Place the center of the ellipse at (0,0)
Since the major axis is equal to 2a and the middle is 9 feet tall, a = 4.5
Since the minor axis is equal to 2b and the length is 6 feet, b = 3
We now have enough information to put the equation into standard form for a vertical ellipse (we do vertical ellipse equation because the major axis is on the y-axis that goes up and down)
(x-h)^2/b^2 + (y-k)^2/a^2=1
x^2/9 + y^2/20.25=1
Now solve for y when x = 1 using algebra. Whatever you get for y is your answer.
Since the major axis is equal to 2a and the middle is 9 feet tall, a = 4.5
Since the minor axis is equal to 2b and the length is 6 feet, b = 3
We now have enough information to put the equation into standard form for a vertical ellipse (we do vertical ellipse equation because the major axis is on the y-axis that goes up and down)
(x-h)^2/b^2 + (y-k)^2/a^2=1
x^2/9 + y^2/20.25=1
Now solve for y when x = 1 using algebra. Whatever you get for y is your answer.
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