Asked by John
Ganymede is a moon of jupiter mass=1.90 x 10^27 kg. it orbits jupiter in a circle of radius 1.07 x 10^9 m. what is ganymede's period in hours?
Answers
Answered by
Damon
G m M / R^2 = m v^2/R
G M/R = v^2
so
v = sqrt (G M/R)
and
T = 2 pi R/v
G M/R = v^2
so
v = sqrt (G M/R)
and
T = 2 pi R/v
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