momentum is conserved
(m1 * v1) + (m2 * v2) = mf * vf
Two molten rocks fly directly toward each other in outer space.
One rock has a mass of 883 kilograms and is moving directly toward the Sun at a velocity of 555 meters per second.
The second rock has a mass of 983 kilograms and is moving directly away from the Sun at a velocity of 629 meters per second.
If the two rocks have a completely inelastic collision, what will be the velocity of the resulting rock?
A. 11,083.72 m/s toward from the Sun.
B. 68.73 m/s away from the Sun.
C. 128,242.00 m/s away from the Sun.
4 answers
Given:
M1 = 883 kg, V1 = 555 m/s.
M2 = 983 kg, V2 = -629 m/s.
V3 = velocity of M1 and M2 after collision.
Momentum before = Momentum after.
M1*V1 + M2*V2 = M1*V3 + M2*V3,
883*555 + 983*(-629) = 883*V3 + 983*V3,
-128,242 = 1866V3,
V3 = -68.73 m/s. = 68.73 m/s away from the sun.
M1 = 883 kg, V1 = 555 m/s.
M2 = 983 kg, V2 = -629 m/s.
V3 = velocity of M1 and M2 after collision.
Momentum before = Momentum after.
M1*V1 + M2*V2 = M1*V3 + M2*V3,
883*555 + 983*(-629) = 883*V3 + 983*V3,
-128,242 = 1866V3,
V3 = -68.73 m/s. = 68.73 m/s away from the sun.
Thank you!
Not necessary to do the problem given the three answer choices.
The second rock has bigger mass and bigger speed AWAY so it will win.
The resulting speed must be smaller than 629 m/s
so
B is the answer
Whoever wrote the problem did that on purpose, otherwise would not have given 128,242 m/s choice
The second rock has bigger mass and bigger speed AWAY so it will win.
The resulting speed must be smaller than 629 m/s
so
B is the answer
Whoever wrote the problem did that on purpose, otherwise would not have given 128,242 m/s choice