Question

A stone is dropped from a building 50 m high. Its acceleration at any time, t, can be approximated by the equation a = -10. How long does it take for the stone to hit the ground at the foot of the building?

Can someone please help me with this. Thanks in advance.
Answer: 3.16 s

Answer 1

distance = 1/2 * acceleration * time^2

-50 = 1/2 * -10 * t^2 ... 10 = t^2

Answer 2

h = ho - 0.5g*t^2 = 0.
50 - 5*t^2 = 0,
t =