Asked by Jake
Simplify. 2/3a*2/a^2
A. 4/3a^2; where a ≠ 0
B. 1/a^2; where a ≠ 0
C. 4/3a^3; where a ≠ 0
D. 4/3a^2
A. 4/3a^2; where a ≠ 0
B. 1/a^2; where a ≠ 0
C. 4/3a^3; where a ≠ 0
D. 4/3a^2
Answers
Answered by
oobleck
I'm assuming you meant
(2/3)a * 2/a^2
= (2a*2)/(3a^2)
= 4/(3a)
well, that wasn't there, so I guess it was
2/(3a) * 2/a^2
= (2*2)/(3a*a^2)
= 4/(3a^3)
(2/3)a * 2/a^2
= (2a*2)/(3a^2)
= 4/(3a)
well, that wasn't there, so I guess it was
2/(3a) * 2/a^2
= (2*2)/(3a*a^2)
= 4/(3a^3)
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