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So I am gonna stack it so u can see what I have and also the equation

3 |1|1 = -4
-1|2|-2 = 1
2|-1|-1 = -1
Looks weird I know. the answer is (5,7,4)
so what I have done with symbolabs was get rid of the (-4,1,-1) which gives me to (5,7,4) but I dont know how to set it up to have the right format.
My instructor even had trouble doing this one as well as myself

9 answers

By format I mean solve by matrix. the original text is
-3x+y+z=-4
-x+2y-2z=1
2x-y-z=-1
two matrices
one matrix

Not sure what you so with symbolabs, but to solve the equation
AX = B
you multiply on the left by A-1, giving
X = A-1B

See it written out at

https://www.wolframalpha.com/input/?i=%7B%7B-3,1,1%7D,%7B-1,2,-2%7D,%7B2,-1,-1%7D%7D*%7B%7Bx%7D,%7By%7D,%7Bz%7D%7D+%3D+%7B%7B-4%7D,%7B1%7D,%7B-1%7D%7D

Shame on your instructor if he had trouble doing it!
He is only math 102 instructor that taught this subject no one even bother with it plus he has never taught 102
I need it to be in 1's and 0's.
In that case, ya got me. Not sure how you would go about converting the matrix to a form involving just 1's and 0's.

Maybe you could clarify a bit... What does the problem actually say? You need to use row manipulations (elimination) to get something on the left with zero entries except for the main diagonal? If so, then just determine

A-1
and AA-1 is the identity matrix.
yes like this
100
010
001
nvm I found it...I had to really dumb it down for the calculator to give more accurate details
I have the url but unforuntately I dont have access to it
thxs oobleck
google gauss jordan reduction
In the end

1 0 0 -1
0 1 0 -1/2
0 0 1 -1/2