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1.15g of acetylsalicylic ia recovered from an aspirim synthesis reaction that began with 2g of salicylic acid, what would be th...Asked by Mouzier
1.15g of acetylsalicylic ia recovered from an aspirim synthesis reaction that began with 2g of salicylic acid, what would be the percentage yield for the preparation? show your computations
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Answered by
Anonymous
(1.15g/2g)x100=????
Answered by
Doc48
Salicylic Acid + Acetic Anhydride.......=>..........Aspirin + Acetic Acid
…..C₇H₆O₃…….. + …..C₄H₆O₃……… =>……...C₉H₈O₄ + HC₂H₃O₂
2g/(138g/mol)….+.....(excess)………=> ?g(Theoretical) + ----------
=0.015mole C₇H₆O₃..…………………=>…0.015mole(180g/mole) = 2.61g Aspirin (Theoretical Yield)
%Yield = (Actual Yield/Theoretical Yield)100% = (1.15g/2.61g)100% = 44.1% Yield
…..C₇H₆O₃…….. + …..C₄H₆O₃……… =>……...C₉H₈O₄ + HC₂H₃O₂
2g/(138g/mol)….+.....(excess)………=> ?g(Theoretical) + ----------
=0.015mole C₇H₆O₃..…………………=>…0.015mole(180g/mole) = 2.61g Aspirin (Theoretical Yield)
%Yield = (Actual Yield/Theoretical Yield)100% = (1.15g/2.61g)100% = 44.1% Yield