Asked by Rogylyn
1.15g of acetylsalicylic ia recovered from an aspirim synthesis reaction that began with 2g of salicylic acid, what would be the percentage yield for the preparation? show your computations
Answers
Answered by
DrBob222
SA = salicylic acid
ASA = aspirin
mols SA = grams/molar mass = ?
mols ASA produced = mols SA
grams ASA = mols ASA x molar mass ASA. This is the theoretical yield (TY)
Actual yield (AY) either 1.15 or 0.15 depending upon how you read the question.
% yield = (AY/TY)*100 = ?
ASA = aspirin
mols SA = grams/molar mass = ?
mols ASA produced = mols SA
grams ASA = mols ASA x molar mass ASA. This is the theoretical yield (TY)
Actual yield (AY) either 1.15 or 0.15 depending upon how you read the question.
% yield = (AY/TY)*100 = ?
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