Asked by Marvelous
                If a man travels 5km,40 degree west of north , then 8km east,find the resultant displacement
            
            
        Answers
                    Answered by
            bobpursley
            
    North: 5cos40
E: 4 sin40+8
    
E: 4 sin40+8
                    Answered by
            Samantha
            
    Both Mrs. Smith and Mrs. Jones had babies the same day in the same hospital. Mrs. Smith took home a baby girl, whom she named Shirley.  Mrs. Jones took home a baby girl, whom she named Jane.  Mrs. Jones began to suspect, however, that her child had been accidentally switched with the Smith baby in the nursery.  Blood tests were made; Mr. Smith was type A, Mrs. Smith was type B, Mr. Jones was type A, Mrs. Jones was type A, Shirley was type O, and Jane was type B. Had a mix-up occurred?
    
                    Answered by
            henry2,
            
    All angles are measured CCW from +x-axis.
Disp. = 5km[130o] + 8km[0o].
X = 5*Cos130 + 8*Cos0 = -3.21 + 8 = 4.78 km.
Y = 5*sin130 + 8*sin0 = 3.83 + 0 = 3.83 km.
Disp. = 4.78 + 3.83i = 6.113 km[38.70].
    
Disp. = 5km[130o] + 8km[0o].
X = 5*Cos130 + 8*Cos0 = -3.21 + 8 = 4.78 km.
Y = 5*sin130 + 8*sin0 = 3.83 + 0 = 3.83 km.
Disp. = 4.78 + 3.83i = 6.113 km[38.70].
                    Answered by
            Joy
            
    I needed a pitagorus theory
    
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