Asked by poppy👌🤔
A tube of uniform cross sectional area closed at one end contain some dry air which is sealed by a thread of Mercury 15.5cm long.when the tube is held vertically with the closed end at the bottom the air column is 22.0cm long, but when it is held horizontally the air column is 26.4cm calculate the atmospheric pressure.?
Answers
Answered by
TimeLost
fn = nV/4L for container open at one end.
remember distance is in cm! therefore d1 = 0.229m.
384 = (1)V/(4)(0.229)
therefore:
V = 350 m/s
remember distance is in cm! therefore d1 = 0.229m.
384 = (1)V/(4)(0.229)
therefore:
V = 350 m/s
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